How do you graph #8y -4# on the coordinate plane?

Question

How do you graph #8y> -4# on the coordinate plane?

Eli Assouline · Accepted Answer

See a solution process below:

Divide each side of the inequality by #color(red)(8)# to solve for #y# while keeping the inequality balanced: #(8y)/color(red)(8) > -4/color(red)(8)# #(color(red)(cancel(color(black)(8)))y)/cancel(color(red)(8)) > -1/2# #y > -1/2# To graph this we will draw a horizontal line at #-1/2# on the vertical axis. The line will be a dashed line because the inequality operator does not contain an "or equal to" clause. We will shade above line because the inequality operator is a "greater than" operator: graph{y > -1/2 [-4, 4, -2, 2]}

Julia Adams · Answer

undefined To graph the inequality $8y > -4$ on the coordinate plane, follow these steps:

1. Start by isolating $y$ to one side of the inequality by dividing both sides by 8. This yields $y > -\frac{1}{2}$.
2. Plot the horizontal line $y = -\frac{1}{2}$ on the coordinate plane.
3. Since the inequality is $y > -\frac{1}{2}$, shade the region above the line (excluding the line itself).
4. Use a dashed line to represent the inequality, indicating that the line itself is not part of the solution set.

So, on the coordinate plane, draw a dashed horizontal line at $y = -\frac{1}{2}$ and shade the region above it.

How do you graph #8y&gt; -4# on the coordinate plane?

How do you graph #8y> -4# on the coordinate plane?