How do you graph #8y> -4# on the coordinate plane?
See a solution process below:
The line will be a dashed line because the inequality operator does not contain an "or equal to" clause.
We will shade above line because the inequality operator is a "greater than" operator:
graph{y > -1/2 [-4, 4, -2, 2]}
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To graph the inequality (8y > -4) on the coordinate plane, follow these steps:
- Start by isolating (y) to one side of the inequality by dividing both sides by 8. This yields (y > -\frac{1}{2}).
- Plot the horizontal line (y = -\frac{1}{2}) on the coordinate plane.
- Since the inequality is (y > -\frac{1}{2}), shade the region above the line (excluding the line itself).
- Use a dashed line to represent the inequality, indicating that the line itself is not part of the solution set.
So, on the coordinate plane, draw a dashed horizontal line at (y = -\frac{1}{2}) and shade the region above it.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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