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How do you graph # -7y + 2x + 14# using intercepts?

Answer 1

Ethan Adkins

The equation given is a line. #-7y+2x+14=0#

We put values for #x# and get values out for #y# or vise versa

So we find two point from which the line goes through

Let's start with #x=0#

#-7y+2x+14=0=>-7y+14=0=>y=2#

so the first point is #A_1(0,2)#

Now let's pu #y=0#

#-7y+2x+14=0=>2x+14=0=>x=-7#

So the second point is #A_2(-7,0)#

The graph is a line that goes through #A_1# and #A_2# graph{-7y+2x+14=0 [-10, 10, -5, 5]}

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Answer 2

Jace Anderson

To graph the equation (-7y + 2x + 14 = 0) using intercepts:

Find the x-intercept by setting (y = 0): (2x + 14 = 0) (2x = -14) (x = -7)
Find the y-intercept by setting (x = 0): (-7y + 14 = 0) (-7y = -14) (y = 2)
Plot the x-intercept at ((-7, 0)) and the y-intercept at ((0, 2)).
Draw a straight line through these two points to represent the graph of the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.