# How do you graph #6x+3y=9# by plotting points?

See a solution process below:

To graph a linear equation you just need to plot two points. First, solve for two points which solve the equation and plot these points:

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-3)^2-0.025)((x-1)^2+(y-1)^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(6x + 3y - 9)(x^2+(y-3)^2-0.025)((x-1)^2+(y-1)^2-0.025)=0 [-10, 10, -5, 5]}

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To graph the equation (6x + 3y = 9) by plotting points:

- Choose values for (x) and solve for (y) to find corresponding points.
- Select at least two different values for (x).
- Substitute each value of (x) into the equation to find the corresponding (y) values.
- Plot each point ((x, y)) on the coordinate plane.
- Connect the points with a straight line.

For example, let's choose (x = 0) and (x = 3):

When (x = 0): [6(0) + 3y = 9 \Rightarrow 3y = 9 \Rightarrow y = 3] So, the point is (0, 3).

When (x = 3): [6(3) + 3y = 9 \Rightarrow 18 + 3y = 9 \Rightarrow 3y = -9 \Rightarrow y = -3] So, the point is (3, -3).

Plotting these points and drawing a line through them, we get the graph of (6x + 3y = 9).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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