How do you graph 4x=-y+2 by plotting points?
Refer explanation section
Given -
4x = -y +2
Solve it for -y
-y = -4x +2
y = 4x - 2
We need minimum two points to fix the straight line
At x = 0; y = 4(0) - 2 = -2
(0, -2) is one point
At y = 0; 4x - 2 = 0
4x = 2
x =
(
x co-ordinate of the second point is a fraction. You can avoid this by suitably taking another value for y, instead of zero.
You shall take 2 as the y- co-ordinate.
At y = 2
4x - 2 = 2
4x = 2 + 2
x =
(1, 2 ) shall be your second point
The two points you are going to plot are -
(0, -2) ; (1, 2)
Plot them and join them with the help o a straight line. graph{4x - 2 [-8.89, 8.89, -4.444, 4.445]}
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To graph the equation 4x = -y + 2 by plotting points, we can rearrange the equation to solve for y in terms of x.
4x = -y + 2 4x - 2 = -y -4x + 2 = y
Now, we can create a table of values for x and find corresponding values for y using the equation y = -4x + 2.
When x = 0, y = 2 When x = 1, y = -2 When x = 2, y = -6
Plotting these points on a graph and connecting them with a straight line will give us the graph of the equation 4x = -y + 2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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