How do you graph #3x+y<=6#?

Answer 1

To graph the inequality, the line 3x+y=6 needs to be graphed first. This can be easily done by determining any two points on the line using the equation.

Choose any arbitrary value of x and find out the corresponding y. In this case if x=0 then y will be 6. Hence one point is (1,6). Like wise have one more point with x=1, which would be (1,3).

Plot the points on the graph and join. The region of the inequality would lie to the left of this line.

[To decide this, choose the point (0,0) which would lie to the left of the line, This point satisfies the given inequality, hence all points to the left of the would satisfy the inequality and would form the region of inequality.]

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Answer 2

To graph the inequality 3x + y ≤ 6, you would first graph the line 3x + y = 6 (the boundary line) using its intercepts or slope-intercept form. Then, since the inequality includes the region below the line, you would shade the area below the line on the graph.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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