# How do you graph #3x+3y=3# by plotting points?

See a solution process below:

First, solve for two points which solve the equation and plot these points:

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-1)^2-0.025)((x-1)^2+y^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x + 3y - 3)(x^2+(y-1)^2-0.025)((x-1)^2+y^2-0.025)=0 [-10, 10, -5, 5]}

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To graph the equation 3x + 3y = 3 by plotting points, you can first rewrite it in slope-intercept form, which is y = mx + b. To do this, solve for y:

3x + 3y = 3 3y = -3x + 3 y = -x + 1

Now that the equation is in slope-intercept form, you can identify the slope (m) and the y-intercept (b). The slope is -1, and the y-intercept is 1.

To graph the equation, start by plotting the y-intercept at (0, 1). Then, use the slope to find additional points. Since the slope is -1 (which can be written as -1/1), you can move down 1 unit and right 1 unit to find another point. Repeat this process to find more points, and then connect them with a straight line.

The graph of the equation 3x + 3y = 3 will be a straight line passing through the points you plotted.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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