How do you graph #3x + 1 < -35# and # -2/3x <=6#?

Answer 1

Solve system:
(1) #3x + 1 < - 35#
(2) #-2x/3 <= 6#

x < -12 --> 3x < -36 (1)

In case x >= -18/2, then x > -9.

+=======|-12-------------|-9========|0======

The solution set includes the critical point (-9). To answer, use the intervals (-infinity, -12) and [-9, +infinity).

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Answer 2

To graph the inequalities 3x + 1 < -35 and -2/3x ≤ 6, first, graph the boundary lines as if they were equalities. Then, determine which side of each line to shade based on the inequality sign.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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