How do you graph #-2y=-x+8# by plotting points?

Question

Eva Adamson · Accepted Answer

#"see explanation"# #"one way is to find the intercepts, that is where the"# #"graph crosses the x and y axes"# #• " let x = 0, in the equation for y-intercept"# #• " let y = 0, in the equation for x-intercept"# #x=0rArr-2y=8rArry=-4larrcolor(red)"y-intercept"# #y=0rArr-x+8=0rArrx=8larrcolor(red)"x-intercept"# #"plot the points "(0,-4)" and "(8,0)# #"draw a straight line through them for graph"# graph{(y-1/2x+4)((x-0)^2+(y+4)^2-0.04)((x-8)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

Savannah Anderson · Answer

undefined To graph the equation -2y = -x + 8 by plotting points, you can follow these steps:

1. Choose values for x and solve for y:
   Let's choose a few values for x, such as 0, 2, and 4.
   
   For x = 0:
   -2y = -0 + 8
   -2y = 8
   y = 8 / -2
   y = -4
   So, when x = 0, y = -4.

For x = 2:
   -2y = -2 + 8
   -2y = 6
   y = 6 / -2
   y = -3
   So, when x = 2, y = -3.

For x = 4:
   -2y = -4 + 8
   -2y = 4
   y = 4 / -2
   y = -2
   So, when x = 4, y = -2.

2. Plot the points (0, -4), (2, -3), and (4, -2) on the coordinate plane.

3. Draw a straight line passing through these points.

4. Label the line as the graph of the equation -2y = -x + 8.