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How do you graph #2y < 8x - 4# on a coordinate graph?

Answer 1

Graph linear inequality: 2y < 8x - 4

First, bring the inequality to standard form: 2y - 8x + 4 < 0. (1) Next, graph the Line -> 2y - 8x + 4 = 0 by its 2 intercepts. To find y-intercept, make x = 0 --> y = - 2. To find x-intercept, make y = 0 --> x = 4/8 = 1/2. To find the solution set of the inequality (1), use the origin as test point. Replace x = 0 and y = 0 into the inequality (1). We get: 4 < 0. Not true! Then, the solution set area doesn't contain O. The area below the line is the answer. Color it. graph{2y - 8x + 4 = 0 [-10, 10, -5, 5]}

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Answer 2

Hazel Anglin

To graph the inequality 2y < 8x - 4 on a coordinate graph:

Rearrange the inequality to y < 4x - 2.
Graph the line y = 4x - 2 as a dashed line.
Since the inequality is y < 4x - 2, shade the region below the dashed line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you graph #2y &lt; 8x - 4# on a coordinate graph?

How do you graph #2y < 8x - 4# on a coordinate graph?