How do you graph #2x+y <=6#?

Answer 1

graph{2x+y<=6 [-10, 10, -5, 5]}

First, you should graph #y=-2x+6#
Since the inequality sign includes the equality, the graph should be a solid line, not a dashed line. If it was #<# or #># then the line should have been dashed.
Then, select a random point on the coordinate plane which is not the line #y=-2x+6#.
If that point satisfies the inequality #2x+y<=6# then that part of the coordinate plane should be shaded. Else, the other part should be dashed.
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Answer 2

To graph the inequality 2x + y ≤ 6, follow these steps:

  1. Start by graphing the boundary line 2x + y = 6 as a solid line.
  2. Choose a test point not on the boundary line and substitute its coordinates into the inequality. Common choices include the origin (0,0) or any other point easily identifiable on the coordinate plane.
  3. If the test point satisfies the inequality, shade the region containing the test point. If not, shade the region opposite to the test point.
  4. The shaded region represents all the points that satisfy the inequality.

This approach ensures that you accurately depict the solution set of the inequality on the coordinate plane.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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