How do you graph #2x + y = –1# by plotting points?

Answer 1

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point:

For #x = 0#
#(2 * 0) + y = -1#
#0 + y = -1#
#y = -1# or #(0, -1)#

Second Point:

For #y = 0#
#2x + 0 = -1#
#2x = -1#
#(2x)/color(red)(2) = -1/color(red)(2)#
#x = -1/2# or #(-1/2, 0)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.025)((x+1/2)^2+y^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x+y+1)(x^2+(y+1)^2-0.025)((x+1/2)^2+y^2-0.025)=0 [-10, 10, -5, 5]}

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Answer 2

To graph the equation (2x + y = -1) by plotting points:

  1. Choose values for (x) and solve for (y) to find points on the line.
  2. Plot at least two points on the coordinate plane.
  3. Draw a straight line passing through the plotted points.

You can choose any values for (x), but common choices include 0, 1, and -1. When (x = 0), (y = -1) according to the equation. When (x = 1) or (-1), you can solve for (y). After plotting these points, draw a straight line through them.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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