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How do you graph #2x+4y=-4# using intercepts?

Answer 1

Avery Alexander

Start by re-writing it as y = some function of x

like so:

#2x + 4y = -4#

...subract 2x from both sides:

#4y = -2x -4#

...divide both sides by 4:

#y = (-x/2) - 1#

Now, the y intercept is the value of y where x = 0 -

#y = 0 - 1 = -1#

For the x intercept, set y = 0 and solve for x:

#0 = (-x/2) -1#

#x/2 = -1#

#x = -2#

so now you have your x & y intercepts. On your graph, plot points (-2, 0) and (0,-1)

And draw your line extending through these points. graph{y = (-x/2)-1 [-10, 10, -5, 5]}

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Answer 2

Eli Assouline

To graph the equation (2x + 4y = -4) using intercepts, we first find the x-intercept by setting (y = 0) and solving for (x), then we find the y-intercept by setting (x = 0) and solving for (y).

Finding the x-intercept: (2x + 4(0) = -4) (2x = -4) (x = -2)
Finding the y-intercept: (2(0) + 4y = -4) (4y = -4) (y = -1)

Plotting the points (-2, 0) and (0, -1) and connecting them with a straight line, we have the graph of (2x + 4y = -4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.