How do you graph #2(y-1) 3(x+1)#?

Question

How do you graph #2(y-1) > 3(x+1)#?

Kennedy Adams · Accepted Answer

First of all, let's manipulate the expression to isolate the #y# term: Now, it's easy to plot the equation #y=3/2 x+ 5/2#, since it is a line. That line is the graph of the equation, which means the set of points
which realize #y=3/2 x + 5/2#, and you want the set of points composed of all the greater #y#'s. This simply means that you must consider the area above the line to solve the equation, as you can see in the graph: graph{y>3/2 x + 5/2 [-10, 10, -5, 5]} Note that the line itself is not part of the solution, because you have the strict inequality and so the set of points #y=3/2 x + 5/2# is not to be considered

Nathan Axel · Answer

undefined To graph the inequality $2(y - 1) > 3(x + 1)$:

1. First, simplify the inequality: $2y - 2 > 3x + 3$.
2. Add 2 to both sides: $2y > 3x + 5$.
3. Divide both sides by 2: $y > \frac{3}{2}x + \frac{5}{2}$.

Now, graph the line $y = \frac{3}{2}x + \frac{5}{2}$ (a dashed line because the inequality is strict). Then, shade the region above the line because it represents where $y$ is greater than $\frac{3}{2}x + \frac{5}{2}$.

How do you graph #2(y-1) &gt; 3(x+1)#?

How do you graph #2(y-1) > 3(x+1)#?