How do you graph #10x=-5y# using the x and y intercepts?

Answer 1

#x=0#

#y=0#

Set x to 0 to find the y-intercept:

#10x=-5y#
#10(0)=-5y#
#0=-5y#
#y=0#

Now set y to 0 to solve for x, or you can notice that since the y-intercept is 0 and this is an equation for a line, the x-intercept must also be 0.

#10x=-5y#
#10x=-5(0)#
#10x=0#
#x=0#

Since both intercepts are the same you need the slope to graph it, put it in slope intercept form:

#y=mx+b#
#10x=-5y#
#-5y = 10x#
#y=-2x#
so your slope #m=-2# now graph:

graph{10x=-5y [-10, 10, -5, 5]}

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Answer 2

To graph the equation (10x = -5y) using the x and y intercepts, first, find the x-intercept by setting (y = 0), then solve for (x):

(10x = -5(0)) (10x = 0) (x = 0)

So the x-intercept is at (0, 0).

Next, find the y-intercept by setting (x = 0), then solve for (y):

(10(0) = -5y) (0 = -5y) (y = 0)

So the y-intercept is also at (0, 0).

Plot these points on the coordinate plane and draw a line passing through them.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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