How do you graph 10x>=10/3# on the coordinate plane?
See a solution process below:
The line will be a solid line because the inequality operator has a "or equal to" clause.
We wil shade to the right of the line because the inequality operator has a "greater than" clause:
graph{x>=1/3 [-8, 8, -4, 4]}
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To graph the inequality (10x \geq \frac{10}{3}) on the coordinate plane, first, graph the line (y = \frac{10}{3}) (which is a horizontal line parallel to the x-axis at (y = \frac{10}{3})).
Since (10x) is greater than or equal to (\frac{10}{3}), the area above or on the line will satisfy the inequality.
You can use a solid line for this graph to indicate that the points on the line are included in the solution. Then, shade the region above the line to represent the solutions to the inequality.
So, you will have a solid line parallel to the x-axis at (y = \frac{10}{3}), and the shaded area will be above or on this line.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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