How do you give one value that makes the inequality #p/8 -2 >6#?

Answer 1
If you're looking for #p#, then you want to isolate it, or get it by itself. by doing that, what you want to do first is get rid of the numbers on one side and have only #p# on one side.
#p/8-2>6#
First, add 2 to move that -2 to the other side #p/8>8#
Next, multiply by 8 to get rid of the denominator of the fraction #p>64#

As an inequality, the answer could be anything that is larger than 64. For example, the answer could be 65 or 65000000 as long as it's bigger than 64

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Answer 2

To solve the inequality ( \frac{p}{8} - 2 > 6 ), we can first add 2 to both sides to isolate the fraction term on the left side:

[ \frac{p}{8} > 6 + 2 ] [ \frac{p}{8} > 8 ]

Next, multiply both sides by 8 to get rid of the fraction:

[ p > 8 \times 8 ] [ p > 64 ]

So, any value of ( p ) greater than 64 would make the inequality true.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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