How do you give a recursive formula for the arithmetic sequence where the 4th term is 3; 20th term is 35?

Answer 1

Refer to explanation

The general arithmetic progression formula is

#a_n=a_1+(n-1)*d# where
#a_n# is the n-th term in the sequence #a_1# is the first term in the sequence #d# is the common difference
We know that #a_4=3# and #a_20=35# so

#a_20-a_4=(a_1+19d)-(a_1+3d)=16d=> 16d=32=>d=2#

Hence the formula becomes #a_n=a_1+2*(n-1)#
for #n=4# we have that
#a_4=a_1+6=>a_1=3-6=>a_1=-3#
Finally we have that #a_n=-3+2*(n-1)#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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