How do you foil #(–x – 3)(3x + 20)#?

Answer 1

#(–x – 3)(3x + 20)=color(blue)(-(3x^2+29x+60)#

The expression is :# (-x−3)(3x +20)#

F O I L entails performing the following tasks in the specified order:

1) product of First terms :#(color(blue)(-x and 3x))#+
2)product of Outside terms:#(color(blue)(-x and 20))#+
3)product of Inside terms:#(color(blue)(-3 and 3x))#+
4)product of Last terms:#(color(blue)(-3 and 20))#
1) #-x *3x=color(blue)(-3x^2) +#
2) #-x* 20=color(blue)(-20x)+#
3) #-3 * 3x = color(blue)(-9x)+#
4) #-3 *20 = color(blue)(-60#

incorporating every term

#=color(blue)(-3x^2-20x-9x-60# #=color(blue)(-3x^2-29x-60# #=color(blue)(-(3x^2+29x+60)#
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Answer 2

To foil the expression (-x - 3)(3x + 20), you need to multiply each term in the first expression by each term in the second expression, and then combine like terms.

First, multiply -x by 3x, then by 20. Next, multiply -3 by 3x, then by 20. Combine like terms to simplify the expression.

The result after multiplying and combining like terms is:

-3x^2 - 20x - 9x - 60

Finally, combine like terms:

-3x^2 - 29x - 60

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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