How do you foil #(7x + 7)(5x – 4)#?

Answer 1

#=color(blue)(35x^2+7x-28#

The expression is :# (7x+7)(5x-4)#

F O I L entails performing the following tasks in the specified order:

1) product of First terms :#(color(blue)(7x and 5x))#+
2)product of Outside terms:#(color(blue)(7x and -4))#+
3)product of Inside terms:#(color(blue)(7 and 5x))#+
4)product of Last terms:#(color(blue)(7 and -4))#
1) #7x*5x=color(blue)(35x^2) +#
2) #7x * -4=color(blue)(-28x)+#
3) #7 * 5x = color(blue)(35x)+#
4) #7 *-4 = color(blue)(-28#

incorporating every term

#=color(blue)(35x^2-28x+35x-28# #=color(blue)(35x^2+7x-28#
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Answer 2

To foil (7x + 7)(5x – 4), you multiply the terms in each set of parentheses together, then combine like terms. This results in the following:

(7x * 5x) + (7x * -4) + (7 * 5x) + (7 * -4) = 35x^2 - 28x + 35x - 28 = 35x^2 + 7x - 28

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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