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How do you foil #(–14x + 11)(–9x + 19)#?

Answer 1

Savannah Anderson

#=color(blue)(126x^2-365x+209#

The expression is :#(–14x+11)(–9x+19)#

F O I L entails performing the following tasks in the specified order:

1) product of First terms :#(color(blue)(-14x and -9x))#+

2)product of Outside terms:#(color(blue)(-14x and 19))#+

3)product of Inside terms:#(color(blue)(11 and -9x))#+

4)product of Last terms:#(color(blue)(11 and 19))#

1) #-14x *-9x=color(blue)(126x^2) +#

2) #-14x * 19=-color(blue)(266x)+#

3) #11 * -9x = color(blue)(-99x)+#

4) #11 *19 = color(blue)209#

incorporating every term

#=color(blue)(126x^2-266x-99x+209# #=color(blue)(126x^2-365x+209#

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Answer 2

Genesis Allen

To foil (–14x + 11)(–9x + 19), apply the FOIL method: Multiply the First terms, Outer terms, Inner terms, and Last terms, and then combine like terms. This yields: ( (-14x) \times (-9x) + (-14x) \times 19 + 11 \times (-9x) + 11 \times 19 ). Simplify each term and combine like terms to get the final result.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.