How do you find two numbers whose difference is 4 and the difference of their square is 88?

Answer 1

#x=13#
#y=9#

How do you find two numbers whose difference is 4 and the difference of their square is 88?

Solution:

let #x=#the larger number let #y=#the smaller number
#x-y=4#first equation #x^2-y^2=88#second equation

Substitute the first in to the second equation

#x^2-y^2=88#second equation #(y+4)^2-y^2=88# #y^2+8y+16-y^2=88# #8y=88-16# #8y=72# #y=9#
Solve for #x# using first equation
#x-y=4#first equation #x-9=4# #x=9+4# #x=13#

God bless... I hope the explanation is useful.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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