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How do you find two integers whose sum is 6 and with a difference of 4?

Answer 1

I found #5# and #1#

yo can call your integers #x# and #y# and form the two equations: #x+y=6# #x-y=4# from the first you have: #x=6-y# that substituted into the second gives: #6-y-y=4# rearranging: #2y=2# #y=2/2=1# Back into #x=6-y# #x=6-1=5#

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Answer 2

Eva Abramson

Let's denote the two integers as ( x ) and ( y ).

Given that their sum is 6, we have the equation ( x + y = 6 ).

Also, given that their difference is 4, we have the equation ( x - y = 4 ).

Now, we can solve these two equations simultaneously to find the values of ( x ) and ( y ).

Adding the two equations together, we get:

( (x + y) + (x - y) = 6 + 4 ) ( 2x = 10 ) ( x = 5 )

Substitute ( x = 5 ) into either of the original equations to solve for ( y ):

( 5 + y = 6 ) ( y = 1 )

So, the two integers are 5 and 1, as ( x = 5 ) and ( y = 1 ) satisfy both conditions (sum of 6 and difference of 4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.