How do you find two consecutive odd numbers whose sum is 276?

Answer 1

#137 and 139#

Let the two consecutive odd numbers be: #(2n-1) and (2n+1) : n in ZZ#
We are told that their sum is #276#
Hence, #(2n-1) + (2n+1) = 276#
#4n = 276 -> n = 69#
So, our first number is: #2xx69-1 = 137#
and the second number is: #139#
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Answer 2

The two consecutive odd numbers are #137# and #139#.

Consecutive means following continuously, or in an unbroken sequence.

An example of two consecutive odd numbers would be #1# and #3# or like #77# and #79#.
First, divide #276# by #2#: #276/2 = 138#
That means #138 + 138 = 276#.
To make them two consecutive odd numbers, we can subtract #1# from one of the #138#s and add #1# to one of the #138#s: #138 - 1 = 137#
#138 + 1 = 139#
When we add them up together, we still get #276#.
Therefore, the two consecutive odd numbers are #137# and #139#.

Hope this helps!

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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