How do you find three consecutive odd integers that have a sum of 123?

Answer 1

#39, 41, 43#

Odd integers that are consecutive are #2# apart.
So if the smallest odd integer is called #n#, then the next two odd integers are #n+2# and #n+4#.
We want the sum to be #123#, so
#n + (n+2) + (n+4) = 123#
#3n+6=123#
#3n = 117#
#n = 39#
So the three consecutive odd numbers are: #39, 41, 43#
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Answer 2

Let's denote the first odd integer as ( x ). Since consecutive odd integers are 2 units apart, the next two consecutive odd integers would be ( x + 2 ) and ( x + 4 ). We know that the sum of these three consecutive odd integers is 123, so we can write the equation ( x + (x + 2) + (x + 4) = 123 ). By solving this equation, we can find the value of ( x ) and then determine the consecutive odd integers.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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