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How do you find three consecutive integers whose sum is 171?

Answer 1

Ethan Adkins

Let the integers be #n-1#, #n# and #n+1#.

Then

#171 = (n-1)+n+(n+1) = n-1+n+n+1 = 3n#

Divide both ends by #3# to get

#n=57#

So the three consecutive integers are #56#, #57#, #58#.

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Answer 2

Ethan Adkins

Let ( x ) represent the first of the three consecutive integers. Then the next two consecutive integers would be ( x + 1 ) and ( x + 2 ).

To find their sum, we add them together and set it equal to 171:

[ x + (x + 1) + (x + 2) = 171 ]

Combine like terms:

[ 3x + 3 = 171 ]

Subtract 3 from both sides:

[ 3x = 168 ]

Divide both sides by 3:

[ x = 56 ]

So, the three consecutive integers are 56, 57, and 58.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.