How do you find three consecutive even integers whose sum is 138?
The integers are:
The three consecutive even numbers can be represented as follows:
The whole numbers are:
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Let's represent the three consecutive even integers as x, x + 2, and x + 4.
The sum of these three consecutive even integers is given by:
x + (x + 2) + (x + 4) = 138
Combine like terms:
3x + 6 = 138
Subtract 6 from both sides:
3x = 132
Divide both sides by 3:
x = 44
So, the three consecutive even integers are 44, 46, and 48.
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Let ( n ) represent the first even integer. Then, the next two consecutive even integers would be ( n + 2 ) and ( n + 4 ). To find three consecutive even integers whose sum is 138, we set up the equation ( n + (n + 2) + (n + 4) = 138 ) and solve for ( n ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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