# How do you find the zeros, real and imaginary, of #y=--x^2 +6x +8# using the quadratic formula?

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To find the zeros of the quadratic function y = -x^2 + 6x + 8 using the quadratic formula, first identify the coefficients: a = -1, b = 6, and c = 8. Then apply the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a). Substituting the values, you get: x = (-(6) ± √((6)^2 - 4(-1)(8))) / (2(-1)). Simplify inside the square root, then solve for the real and imaginary zeros accordingly.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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