How do you find the zeros of # y = -9x^2 + 18x -2 # using the quadratic formula?
(3 +- sqrt7)/3
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To find the zeros of the quadratic equation (y = -9x^2 + 18x - 2) using the quadratic formula, we use the formula (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}), where (a = -9), (b = 18), and (c = -2). Substituting these values into the formula, we get:
[x = \frac{{-18 \pm \sqrt{{18^2 - 4(-9)(-2)}}}}{{2(-9)}}]
Simplify inside the square root:
[x = \frac{{-18 \pm \sqrt{{324 - 72}}}}{{-18}}]
[x = \frac{{-18 \pm \sqrt{{252}}}}{{-18}}]
[x = \frac{{-18 \pm \sqrt{{36 \cdot 7}}}}{{-18}}]
[x = \frac{{-18 \pm 6\sqrt{7}}}{{-18}}]
[x = \frac{{-3 \pm \sqrt{7}}}{{-3}}]
So, the zeros of the quadratic equation (y = -9x^2 + 18x - 2) are (x = \frac{{3 \pm \sqrt{7}}}{{3}}).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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