# How do you find the zeros of the function #f(x)=(x^2+3x-4)/(x^2+9x+20)#?

By finding the zeros of the numerator and checking if they do not occur in the denominator. Here we have x=1 as zero.

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To find the zeros of the function f(x) = (x^2 + 3x - 4)/(x^2 + 9x + 20), we set the numerator equal to zero and solve for x. The zeros of the function are the values of x that make the numerator equal to zero.

Setting the numerator equal to zero: x^2 + 3x - 4 = 0

Factoring the quadratic equation: (x + 4)(x - 1) = 0

Setting each factor equal to zero and solving for x:

x + 4 = 0 --> x = -4

x - 1 = 0 --> x = 1

Therefore, the zeros of the function f(x) are x = -4 and x = 1.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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