How do you find the zeros of the function #f(x)=(3x^2-18x+24)/(x-6)#?
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To find the zeros of the function f(x) = (3x^2 - 18x + 24)/(x - 6), we need to set the numerator equal to zero and solve for x.
Setting the numerator equal to zero: 3x^2 - 18x + 24 = 0
Factoring out a common factor of 3: 3(x^2 - 6x + 8) = 0
Factoring the quadratic expression: 3(x - 2)(x - 4) = 0
Setting each factor equal to zero and solving for x: x - 2 = 0 --> x = 2 x - 4 = 0 --> x = 4
Therefore, the zeros of the function f(x) = (3x^2 - 18x + 24)/(x - 6) are x = 2 and x = 4.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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