How do you find the zeros of the function #f(x)=(3x^2-18x+24)/(x-6)#?

Answer 1

#x=2,x=4#

#"zeros are the values of x that make f(x) equal zero"#
#rArr(3x^2-18x+24)/(x-6)=0#
#"the numerator therefore must equal zero"#
#"solve " 3x^2-18x+24=0" for zeros"#
#3(x^2-6x+8)=0larr" common factor of 3"#
#3(x-2)(x-4)=0#
#"equate each factor to zero"#
#x-2=0tox=2#
#x-4=0tox=4#
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Answer 2

To find the zeros of the function f(x) = (3x^2 - 18x + 24)/(x - 6), we need to set the numerator equal to zero and solve for x.

Setting the numerator equal to zero: 3x^2 - 18x + 24 = 0

Factoring out a common factor of 3: 3(x^2 - 6x + 8) = 0

Factoring the quadratic expression: 3(x - 2)(x - 4) = 0

Setting each factor equal to zero and solving for x: x - 2 = 0 --> x = 2 x - 4 = 0 --> x = 4

Therefore, the zeros of the function f(x) = (3x^2 - 18x + 24)/(x - 6) are x = 2 and x = 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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