How do you find the zeros of #g(x)=33x^2-9x-24#?

Answer 1

#x=1,x=-24/33#

#"note that " g(1)=0rArr(x-1)" is a factor"#
#g(x)=color(red)(33x)(x-1)color(magenta)(+33x)-9x-24#
#color(white)(g(x))=color(red)(33x)(x-1)color(red)(+24)(x-1)color(magenta)(+24)-24#
#color(white)(g(x))=color(red)(33x)(x-1)color(red)(+24)(x-1)+0#
#rArrg(x)=(x-1)(color(red)(33x+24))=0#
#"equate each factor to zero"#
#x-1=0rArrx=1larr" is a zero"#
#33x+24=0rArrx=-24/33larr" is a zero"#
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Answer 2

To find the zeros of ( g(x) = 33x^2 - 9x - 24 ), you can use the quadratic formula ( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} ), where ( a = 33 ), ( b = -9 ), and ( c = -24 ). Plugging these values into the formula will give you the zeros of the function.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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