# How do you find the zeros of #f(x) = x^4 - x^3 - 6x^2 + 4x + 8#?

Zeros:

#x = -1#

#x = 2# with multiplicity#2#

#x = -2#

Note that in the remaining cubic, the ratio of the first and second terms is the same as that between the third and fourth terms. So this will factor by grouping:

Hence the other zeros are:

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To find the zeros of (f(x) = x^4 - x^3 - 6x^2 + 4x + 8), you need to solve the equation (x^4 - x^3 - 6x^2 + 4x + 8 = 0). This can be done using various methods such as factoring, synthetic division, or numerical methods like graphing or using a calculator. Since factoring may not be straightforward for this polynomial, you might need to use numerical methods or software to approximate the roots.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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