# How do you find the zeros for the function #f(x)=(x^2-x-12)/(x-2)#?

X= 4 and x= -3

You can find the zeros only when the nominator is equal to 0

So it's not necessary to care about the denominator in here

You can solve by factorisation, quadratic formula, or completing square

And you can solve it

You get x= 4 and x= -3

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graph{((x+3)(x-4))/(x-2) [-18.01, 18.04, -9.01, 8.99]}

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To find the zeros of the function f(x) = (x^2 - x - 12)/(x - 2), we need to set the numerator equal to zero and solve for x.

(x^2 - x - 12) = 0

Factoring the quadratic equation, we have:

(x - 4)(x + 3) = 0

Setting each factor equal to zero, we get:

x - 4 = 0 or x + 3 = 0

Solving for x in each equation, we find:

x = 4 or x = -3

Therefore, the zeros of the function f(x) are x = 4 and x = -3.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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