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How do you find the zeroes for #y=x^2+3x+2#?

Answer 1

You may first want to factorise the equation.

You may notice that #2=1*2# and #3=1+2# This leads to: #y=x^2+3x+2=(x+1)*(x+2)# For #y=0# either one of the factors need to be #=0#

This leads to #x=-1orx=-2#

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Answer 2

Ethan Adkins

To find the zeroes of the quadratic equation (y = x^2 + 3x + 2), you need to set (y) to zero and solve for (x). This can be done by factoring, completing the square, or using the quadratic formula. In this case, factoring is the simplest method. Factoring the quadratic equation (x^2 + 3x + 2) yields ((x + 2)(x + 1)). Setting each factor equal to zero and solving for (x), we get (x = -2) and (x = -1). So, the zeroes of the equation are (x = -2) and (x = -1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.