# How do you find the zeroes for #R( x) = (3x)/(x^2 - 2x)#?

To find the zeroes of R(x) = (3x)/(x^2 - 2x), we need to set the numerator equal to zero and solve for x.

Setting 3x = 0, we find that x = 0.

Next, we need to consider the denominator. Setting x^2 - 2x = 0, we can factor out an x: x(x - 2) = 0.

This equation is satisfied when either x = 0 or x - 2 = 0.

Therefore, the zeroes of R(x) are x = 0 and x = 2.

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graph{3x/(x^2-2x) [-10, 10, -5, 5]}

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