How do you find the zero(s) of #f(x)=-3/2x+9#?
Elijah AllenThe zeros of f(x) are the value/s of x that make f(x) equal zero.
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Sadie AckermanTo find the zero(s) of ( f(x) = -\frac{3}{2}x + 9 ), set ( f(x) ) equal to 0 and solve for ( x ):
[ -\frac{3}{2}x + 9 = 0 ]
[ -\frac{3}{2}x = -9 ]
[ x = \frac{-9}{-\frac{3}{2}} = \frac{-9}{-3/2} ]
[ x = \frac{-9 \cdot -2}{3} = \frac{18}{3} = 6 ]
So, the zero of ( f(x) = -\frac{3}{2}x + 9 ) is ( x = 6 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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