# How do you find the y intercept, axis of symmetry and the vertex to graph the function #f(x)=x^2-9#?

Vertex is at

axis of symmetry is

graph{x^2-9 [–40,–40,–20,-20]} [Ans]

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To find the y-intercept of the function f(x) = x^2 - 9, substitute x = 0 into the equation: f(0) = (0)^2 - 9 = -9. So, the y-intercept is -9.

To find the axis of symmetry of the function, we use the formula for the axis of symmetry of a parabola given by x = -b/2a. For the function f(x) = x^2 - 9, the coefficient of x is 0, so the axis of symmetry is x = 0.

To find the vertex of the parabola, we use the axis of symmetry. Since the axis of symmetry is x = 0, the x-coordinate of the vertex is 0. To find the y-coordinate of the vertex, we substitute x = 0 into the function: f(0) = (0)^2 - 9 = -9. So, the vertex of the parabola is (0, -9).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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