# How do you find the x values at which #f(x)=3x-cosx# is not continuous, which of the discontinuities are removable?

graph{3x-cosx [-30, 30, -30, 30]}

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To find the x values at which f(x)=3x-cosx is not continuous, we need to identify the points where the function has discontinuities.

The function f(x)=3x-cosx is a combination of a polynomial function (3x) and a trigonometric function (cosx).

The polynomial function 3x is continuous everywhere, so it does not contribute to any discontinuities.

The trigonometric function cosx is also continuous everywhere. However, it has discontinuities at the points where the denominator of the function becomes zero. In this case, the denominator is not present, so there are no discontinuities caused by the trigonometric function.

Therefore, the function f(x)=3x-cosx is continuous for all x values. There are no points of discontinuity, and thus, there are no removable discontinuities.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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