# How do you find the x intercept of #f(x) = (x^2+9x)/(x^2+3x-4)#?

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To find the x-intercept of a function, we set the value of y (or f(x)) to zero and solve for x. In this case, we have the function f(x) = (x^2+9x)/(x^2+3x-4). To find the x-intercept, we set f(x) equal to zero:

0 = (x^2+9x)/(x^2+3x-4)

Next, we can multiply both sides of the equation by (x^2+3x-4) to eliminate the denominator:

0 * (x^2+3x-4) = (x^2+9x)

Expanding the equation, we get:

0 = x^2 + 9x

Now, we can factor out an x from the right side of the equation:

0 = x(x + 9)

Setting each factor equal to zero, we have two possible solutions:

x = 0 or x + 9 = 0

Solving for x in each equation, we find:

x = 0 or x = -9

Therefore, the x-intercepts of the function f(x) = (x^2+9x)/(x^2+3x-4) are x = 0 and x = -9.

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