How do you find the x and y intercepts of #y=3x-2#?

Question

Eva Abramson · Accepted Answer

#"x-intercept "=2/3," y-intercept "=-2# #"To find the intercepts, that is where the graph crosses"# #"the x and y axes"# #• " let x = 0, in the equation for y-intercept"# #• " let y = 0, in the equation for x-intercept"# #x=0rArry=0-2=-2larrcolor(red)"y-intercept"# #y=0rArr3x-2=0rArrx=2/3larrcolor(red)"x-intercept"# graph{(y-3x+2)((x-0)^2+(y+2)^2-0.04)((x-2/3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

Ethan Adkins · Answer

#"y-intercept " = (0, -2) or -2#
#"y-intercept " = (2/3, 0) or 2/3# The y-intercept is when the value of #x = 0#. Therefore, plugging in the value of #x# into the equation: #3(0) - 2 = -2 " So, " y = -2# This is for the y-intercept The x intercept is when #y = 0#, substituting this into the equation gives us: #0 = 3x - 2# It is possible to rearrange this: # 0 -3x = 3x - 3x - 2# # 3x = 2# # x = 2/3#

Kennedy Adams · Answer

undefined To find the x-intercept, set y = 0 and solve for x. To find the y-intercept, set x = 0 and solve for y.

For x-intercept:
0 = 3x - 2
x = 2/3

For y-intercept:
y = 3(0) - 2
y = -2

The x-intercept is (2/3, 0) and the y-intercept is (0, -2).