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How do you find the X and Y intercepts of -x+2y=8?

Answer 1

x-intercept: #(-8)#
y-intercept: #4#

The x-intercept is the value of #x# where the graph crosses the X-axis; for all points on the X-axis, #y=0# Therefore the x-intercept is the value of #x# when #y=0# for the given equation (#-x+2y=8#)

#color(white)("XXX")-x+2(0)=8# #color(white)("XXX")x=-8#

Similarly the y-intercept is the value of #y# when #x=0# in the given equation.

#color(white)("XXX")-0+2y=8# #color(white)("XXX")y=4#

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Answer 2

Eva Adamson

To find the x-intercept, set y to 0 and solve for x. To find the y-intercept, set x to 0 and solve for y.

For the equation -x + 2y = 8:

To find the x-intercept:

Set y to 0: -x + 2(0) = 8
Solve for x: -x = 8
Divide both sides by -1: x = -8

So the x-intercept is (-8, 0).

To find the y-intercept:

Set x to 0: -0 + 2y = 8
Simplify: 2y = 8
Divide both sides by 2: y = 4

So the y-intercept is (0, 4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.