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How do you find the x and y intercepts of #6x+2y=10#?

Answer 1

Eva Adamson

The intercepts are at #(1 2/3, 0) and (0, 5)#

Leave the equation #6x +2y = 10# in this form.

All along the #x-#axis, #y=0" "# All along the #y-#axis, #x=0#

To find the #y-#intercept, set #x=0#

#6(0) + 2y = 10" "rarr y = 5#

To find the #x-#intercept, set #y=0#

#6x + 2(0) = 10" " rarr x = 10/6 = 5/3 = 1 2/3#

The intercepts are at #(1 2/3, 0) and (0, 5)#

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Answer 2

Savannah Anderson

To find the x-intercept, set y to 0 and solve for x. To find the y-intercept, set x to 0 and solve for y.

For the x-intercept:
6x + 2(0) = 10
6x = 10
x = 10/6 = 5/3

For the y-intercept:
6(0) + 2y = 10
2y = 10
y = 10/2 = 5

The x-intercept is (5/3, 0) and the y-intercept is (0, 5).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.