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How do you find the x and y intercepts for #y=9/5x+3/5#?

Answer 1

x = #- 1/3 and y = 3/5 #

# y = 9/5 #x + #3/5 # is a linear equation ie. a straight line.

when a straight line crosses the x-axis the value of it's y-coordinate will be 0. By substituting y = 0 into the equation will enable us to find the corresponding x-coordinate.

y=0 : # 9/5# x + # 3/5# = 0

# 9/5 #x = #-3/5#

# x= -3/5 / 9/5 #

# x= -3/5 xx 5/9# # x = -1/3 # similarly when the straight line crosses the y-axis the value of it's x-coordinate will be 0 and by substituting x =0 into the equation will give the corresponding y- intercept.

x=0 : y = # 9/5 xx 0 + 3/5 # # y= 0 + 3/5 = 3/5 #

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Answer 2

Jameson Allen

To find the x-intercept, set (y = 0) in the equation and solve for (x). To find the y-intercept, set (x = 0) in the equation and solve for (y).

For (y = \frac{9}{5}x + \frac{3}{5}):

To find the x-intercept, set (y = 0): (0 = \frac{9}{5}x + \frac{3}{5}), then solve for (x).
To find the y-intercept, set (x = 0): (y = \frac{9}{5}(0) + \frac{3}{5}), then solve for (y).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.