Home > Algebra > Intercepts by Substitution

How do you find the x and y intercepts for #y= - 6/5x + 6#?

Answer 1

Isaiah Anthony

#x#-intercept at 5,
#y#-intercept at -6.

Since this is a linear function with a #b#-value and a slope, it must cross the #x# and #y# axes at some point.

To solve for the #y#-intercept, let #x# = #0#:

#y# = #-(6/5)#(#0#)+6 #y# = 6

To solve for the #x# - intercept, let #y# = #0#:

#0#= #-(6/5)(x)#+6 #-6=-(6/5)(x)# #-30=-6x# #x=5#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Jameson Allen

To find the x-intercept, set y to 0 and solve for x. To find the y-intercept, set x to 0 and solve for y.

For the x-intercept: 0 = -6/5x + 6 x = 5

For the y-intercept: y = -6/5(0) + 6 y = 6

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.