How do you find the x and y intercepts for #y=-5x+10#?
x-intercept = 2 , y-intercept = 10
This is the equation of a straight line. When this line crosses the x-axis , the y-coord will be zero. By letting y = 0 and substituting into the equation , we will obtain the x-intercept.
y = 0 : -5x + 10 = 0 → -5x = - 10 → x = 2
Similarly for when the line crosses the y-axis , the x-coord will be zero. Let x = 0 to find y-intercept.
x = 0 : y = 10
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To find the x-intercept, set ( y = 0 ) and solve for x. To find the y-intercept, set ( x = 0 ) and solve for y. For ( y = -5x + 10 ), the x-intercept is (2, 0) and the y-intercept is (0, 10).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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