How do you find the x and y intercepts for #y=3x-2#?

Question

Ethan Adkins · Accepted Answer

#y = -2#
#x = 0#
#(0,-2)# Add two to both sides. #y = 3x - 2# to #y + 2 = 3x# Next, instead of #x#, put #y + 2#. #y + 2= 3(y+2)# Then, multiply #3# by #y# and #3# by #2#. #y +2= 3y + 6# Subtract #y# from both sides. #2 + y = 3y + 6# to #2 = 2y + 6# Subtract #6# from both sides. #2 = 2y + 6# to #-4 = 2y# Divide both sides by #2#. #-4 = 2y# to #-2 = y# Go back to the original equation. Replace #y# with #-2#. #y = 3x - 2# to #-2 = 3x - 2# Add #2# to both sides. #-2 = 3x - 2# to #0 = 3x# Divide both sides by #3#. #0 = 3x# to #0 = x# Hope that helped! : )

Eli Assouline · Answer

The x-intercept is #(2/3,0)#.

The y-intercept is #(0,-2)#.

Given: #y=3x-2# X-intercept: value of #x# when #y=0#. Substitute #0# for #y#. #0=3x-2# Add #2# to both sides. #2=3x# Divide both sides by #3#. #2/3=x# The x-intercept is #(2/3,0)#. Y-intercept: value of #y# when #x=0# #y=3x-2# is the slope-intercept form for a linear equation: #y=mx+b#, where: #m# is the slope, and #b# is the y-intercept. Therefore, the y-intercept is #(0,-2)#. You can also substitute #2# for #x# and solve for #y#. #y=3(0)-2# #y=-2# The y-intercept is #(0,-2)#. graph{y=3x-2 [-10, 10, -5, 5]}

Avery Alexander · Answer

undefined To find the x-intercept, set y = 0 and solve for x. To find the y-intercept, set x = 0 and solve for y.

For y = 3x - 2:
To find the x-intercept, set y = 0:
0 = 3x - 2
Solve for x: x = 2/3

To find the y-intercept, set x = 0:
y = 3(0) - 2
Solve for y: y = -2

So, the x-intercept is (2/3, 0) and the y-intercept is (0, -2).