How do you find the x and y intercepts for #y = -2x + 3#?

Answer 1

#"x-intercept "=3/2," y-intercept "=3#

#"to find the intercepts"#
#• " let x = 0, in the equation for y-intercept"#
#• " let y = 0, in the equation for x-intercept"#
#x=0rArry=0+3=3larrcolor(red)"y-intercept"#
#y=0rArr-2x+3=0rArrx=3/2larrcolor(red)"x-intercept"# graph{-2x+3 [-10, 10, -5, 5]}
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Answer 2

see a step solution process below;

#y = - 2x + 3#

Since the origin point of intersection is always zero, hence we would use its origin point to locate their intercepts.

To find the intercept of #x#, let #y = 0#
#y = -2x + 3#, where #y = 0#
#0 = -2x + 3#
#2x = 3#
#x = 3/2 = 1.5#
Similarly, to find the intercept of #y#, let #x = 0#
#y = -2x + 3#, where #x = 0#
#y = -2(0) + 3#
#y = 0 + 3#
#y = 3#
Hence the #x and y# intercepts of the equation are #1.5 and 3# respectively..
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Answer 3

To find the x-intercept, set y equal to zero and solve for x. To find the y-intercept, set x equal to zero and solve for y. For the given equation y = -2x + 3, the x-intercept is (1.5, 0) and the y-intercept is (0, 3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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