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How do you find the x and y intercepts for #y= 2/3x + 4#?

Answer 1

Abigail Allen

#x=-6#
#y=4#

To find the x-intercept, substitute #y=0# into the equation (as the graph crosses the x-axis when y is zero).

#0=2/3x+4# #2/3x=-4# #x=-4/(2/3)# #x=-4*(3/2)# #x=-6#

Similarly, to find the y-intercept, substitute #x=0# into the equation.

#y=2/3*0+4# #y=4#

Hope this helps :)

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Answer 2

Eli Assouline

To find the x-intercept, set y = 0 and solve for x:

0 = (2/3)x + 4 -4 = (2/3)x -6 = x

So, the x-intercept is at (-6, 0).

To find the y-intercept, set x = 0 and solve for y:

y = (2/3)(0) + 4 y = 4

So, the y-intercept is at (0, 4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.