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How do you find the x and y intercepts for #2x + 4y = -8#?

Answer 1

Eva Adamson

See explanation.

To find #x# interxept of a function you have to substitute #0# for #y# and solve the equation for #x#:

The #x# intercept is the point #(-4,0)#.

To find #y# intercept you have to substitute #0# for #x# and solve the equation for #y#:

The #y# intercept is the point #(0,-2)#.

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Answer 2

Isaiah Anthony

x-intercept = #(-4,0)#
y-intercept = #(0,-2#)

x-intercept is when #y=0#
y-intercept is when #x=0#

Step 1:
Lets find the x-intercept by putting #y=0#

#2x+4y=-8#

#2x +(4 xx 0) = -8#

#2x +0 = -8#

#2x=-8#

#x= -8/2#

#x = -4# ------> x-intercept is #(-4,0)#

Step 2:
Lets find the y-intercept by putting #x=0#

#2x+4y=-8#

#(2 xx 0) +4y = -8

#0 + 4y = -8#

#4y=-8#

#y=-8/4#

#y = -2# -----> y-intercept is #(0,-2)#

if we plot the graph, we get the same.

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Answer 3

Isaiah Anthony

To find the x-intercept, set y = 0 and solve for x. To find the y-intercept, set x = 0 and solve for y.

For x-intercept: 2x + 4(0) = -8 x = -4

For y-intercept: 2(0) + 4y = -8 y = -2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.