How do you find the x and y intercept of #5x + 6y = −30#?

Answer 1

x-intercept = - 6
y-intercept = -5

This is the equation of a line. When the line crosses the x-axis, #color(blue)"x-intercept"#, the value of the y-coordinate will be zero. Substituting y = 0 into the equation and solving for x gives the x-intercept.
y=0 : 5x+0=-30#rArrx=-6" x-intercept"#
Similarly when the line crosses the y-axis, #color(blue)"y-intercept"#, the value of the x-coordinate will be zero.
x = 0 : 0 + 6y = - 30 #rArry=-5 " y-intercept"# graph{-5/6x-5 [-10, 10, -5, 5]}
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Answer 2

To find the x-intercept, set y = 0 and solve for x. To find the y-intercept, set x = 0 and solve for y.

For x-intercept: [5x + 6(0) = -30] [5x = -30] [x = -6]

For y-intercept: [5(0) + 6y = -30] [6y = -30] [y = -5]

So, the x-intercept is (-6, 0) and the y-intercept is (0, -5).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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